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Clearance Delivery Diode Leakage

 
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MFleming



Joined: 31 Oct 2017
Posts: 17

PostPosted: Tue Dec 29, 2020 8:56 pm    Post subject: Clearance Delivery Diode Leakage Reply with quote

The wiring has begun for my RV-7. I've decided to use fuse blocks for circuit protection.

The architecture will utilize a clearance delivery (CD) buss. The CD buss has a diode installed per Z101B. When applying DC voltage to the CD bus and measuring the voltage at the main buss, there is a 350 to 390 mv reading.

Is that enough to worry about or do I have a bad diode? This is the B&C Essential Bus Diode w/ 8 watt heatsink PN-221-200.

Heres a photo of the fuse blocks while being tested for leakage. You may be able to make out the 351.8 mv leakage.

PS - the wires depicted was replaced with one with heat shrink...yep, I forgot.

http://myplace.frontier.com/~tokosha/avionics/test_diode.jpg


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Michael Fleming
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user9253



Joined: 28 Mar 2008
Posts: 1911
Location: Riley TWP Michigan

PostPosted: Wed Dec 30, 2020 6:15 am    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

A voltage drop across a diode is normal. A drop of o.4 volts is low. It will be
2 or even 3 times that much under heavy load. Power (heat) equals volts
times current. Suppose that the load is 10 amps. 10 amps times 1 volt equal
10 watts. That is a lot of heat and the reason for the heat sink. If you want
to minimize the amount of power lost, a Schottky diode will waste about half
as much as a regular diode.


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Joe Gores
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user9253



Joined: 28 Mar 2008
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Location: Riley TWP Michigan

PostPosted: Wed Dec 30, 2020 6:19 am    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

Use heat conductive paste between the diode and the heat sink.
Otherwise the diode could overheat and fail.
Assuming that the heat sink will be mounted to an aluminum surface, also
use heat conductive paste between the heat sink and mounting surface.


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MFleming



Joined: 31 Oct 2017
Posts: 17

PostPosted: Wed Dec 30, 2020 11:57 am    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

user9253 wrote:
A voltage drop across a diode is normal. A drop of o.4 volts is low. It will be
2 or even 3 times that much under heavy load. Power (heat) equals volts
times current. Suppose that the load is 10 amps. 10 amps times 1 volt equal
10 watts. That is a lot of heat and the reason for the heat sink. If you want
to minimize the amount of power lost, a Schottky diode will waste about half
as much as a regular diode.


So the voltage feedback, leakage is the issue.

The voltage drop when the diode is supplying current to the CD buss from the main buss is expected.

When the CD buss is being fed from the battery and the diode is supposed to prevent the main buss from seeing current is when I'm seeing the 350+ millivolts.

I'm not sure if the feedback through the diode to the main buss is considered OK or not.

user9253 wrote:
Use heat conductive paste between the diode and the heat sink.
Otherwise the diode could overheat and fail.
Assuming that the heat sink will be mounted to an aluminum surface, also
use heat conductive paste between the heat sink and mounting surface.


B&C provided the diode and heat sink as a unit so I'm hopping they assembled it with the proper paste. Would dielectric grease be suitable as a heat sink paste?


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user9253



Joined: 28 Mar 2008
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Location: Riley TWP Michigan

PostPosted: Wed Dec 30, 2020 12:34 pm    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

It is normal to see voltage like you are with no load. Put a load on the main
bus and that voltage will disappear. A 12 volt test light will make a good load.
Use a test light that does not have an internal battery. The test light should
operate off from the aircraft battery. Grease might melt. Home Depot and
Amazon sells part number 98003/202932736


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PostPosted: Wed Dec 30, 2020 8:31 pm    Post subject: Clearance Delivery Diode Leakage Reply with quote

At 09:48 AM 12/30/2020, you wrote:
Quote:
--> AeroElectric-List message posted by: Dick Tasker <dick(at)thetaskerfamily.com>

As far as I can see on your picture, you have no loads anywhere and have the positive supply lead only connected to the CD bus.  Under those conditions any voltages you can measure are pretty much meaningless. A good DVM has a very high input impedance so puts no load on whatever it is measuring.

On the other hand, if there is any load on the main bus then you may have a defective diode. To check, just put some sort of load on the main bus (resistor, light bulb, relay coil, etc.). With a load there I doubt you will see anything (unless the diode bridge is actually bad - pretty unlikely).

Right on! I set up an experiment on
the bench with an exemplar bridge
rectifier. A multimeter set to read
leakage CURRENT indicated less than
0.1 microamps. Changing the meter to
read VOLTS gave an indication on the
order of 400mV.

What you're seeing is normal and expected.


Bob . . .

Un impeachable logic: George Carlin asked, "If black boxes
survive crashes, why don't they make the whole airplane
out of that stuff?"


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PostPosted: Wed Dec 30, 2020 8:38 pm    Post subject: Clearance Delivery Diode Leakage Reply with quote

At 01:57 PM 12/30/2020, you wrote:
Quote:
--> AeroElectric-List message posted by: "MFleming" <sagriver(at)icloud.com>


user9253 wrote:
> A voltage drop across a diode is normal. A drop of o.4 volts is low. It will be
> 2 or even 3 times that much under heavy load. Power (heat) equals volts
> times current. Suppose that the load is 10 amps. 10 amps times 1 volt equal
> 10 watts. That is a lot of heat and the reason for the heat sink. If you want
> to minimize the amount of power lost, a Schottky diode will waste about half
> as much as a regular diode.


So the voltage feedback, leakage is the issue.

The voltage drop when the diode is supplying current to the CD buss from the main buss is expected.

When the CD buss is being fed from the battery and the diode is supposed to prevent the main buss from seeing current is when I'm seeing the 350+ millivolts.

I'm not sure if the feedback through the diode to the main buss is considered OK or not.

Doing the math on your observations:

Assuming a nominal 10,000,000 ohm input impedance
of your multimeter in the voltage mode . . .

E 0.400
I = --- = --------- = 4 NANOAMPS!
R 10,000,000

Some multimeters have as much as 20M Ohms input
impedance which would give you 2 NANOAMPS . . .
quite normal and insignificant.

If you put your multimeter into the current
measuring mode, the impressed current would
be too small to wiggle the display on the
most sensitive scale.


Bob . . .

Un impeachable logic: George Carlin asked, "If black boxes
survive crashes, why don't they make the whole airplane
out of that stuff?"


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MFleming



Joined: 31 Oct 2017
Posts: 17

PostPosted: Thu Dec 31, 2020 10:12 am    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

[quote="nuckolls.bob(at)aeroelect"]At 09:48 AM 12/30/2020, you wrote:
Quote:
--> AeroElectric-List message posted by: Dick Tasker <dick>

As far as I can see on your picture, you have no loads anywhere and have the positive supply lead only connected to the CD bus.� � Under those conditions any voltages you can measure are pretty much meaningless.� A good DVM has a very high input impedance so puts no load on whatever it is measuring.

On the other hand, if there is any load on the main bus then you may have a defective diode.� To check, just put some sort of load on the main bus (resistor, light bulb, relay coil, etc.).� With a load there I doubt you will see anything (unless the diode bridge is actually bad - pretty unlikely).


So this is correct, there are no loads during this test. BUT there is not supposed to be a load or current on the main buss in this photo during the test.

The test was supposed to verify that the diode is doing its job of preventing flow from the CD bus back to the main buss when the CD buss is energized and the main buss is deenergized. The test simulate the CD buss being energized while the master contactor is open, ergo - main bus should show no voltage.

Now if your saying I need a load on the CD buss during this test great...but a load or any current on the main buss would negate the test as far as I can see.

On the other hand it sounds like Bob is saying what I'm seeing is normal...so I think I'll move on to more wiring.


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user9253



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PostPosted: Thu Dec 31, 2020 4:19 pm    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

Check for electricity on the main bus using a test light.
The light will not illuminate. That means there is no voltage on the main bus.
Leave the test light connected to the main bus, then measure the voltage with
the digital meter again. The main bus will now have zero volts. The diode is OK.


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MFleming



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PostPosted: Thu Dec 31, 2020 5:10 pm    Post subject: Re: Clearance Delivery Diode Leakage Reply with quote

user9253 wrote:
Check for electricity on the main bus using a test light.
The light will not illuminate. That means there is no voltage on the main bus.
Leave the test light connected to the main bus, then measure the voltage with
the digital meter again. The main bus will now have zero volts. The diode is OK.


I see....The test light (load) on the main buss drains the residual voltage and kinda make the diode seal better like a check valve with differential pressure would.


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PostPosted: Sun Jan 03, 2021 12:18 pm    Post subject: Clearance Delivery Diode Leakage Reply with quote

At 07:10 PM 12/31/2020, you wrote:
Quote:
--> AeroElectric-List message posted by: "MFleming" <sagriver(at)icloud.com>


user9253 wrote:
> Check for electricity on the main bus using a test light.
> The light will not illuminate. That means there is no voltage on the main bus.
> Leave the test light connected to the main bus, then measure the voltage with
> the digital meter again. The main bus will now have zero volts. The diode is OK.


I see....The test light (load) on the main buss drains the residual
voltage and kinda make the diode seal better like a check valve
with differential pressure would.

No, leakage through the reverse biased diode is
relatively constant irrespective of the load. Consider
the attached drawing. The red boxes represent your
ship's battery and the diode under study. I've
depicted a reverse leakage resistor RL2 around the
diode.

To read 0.4v across a 10M resistor in series (your
voltmeter) describes a ratio:

RL2 + 10M 10M
---------- = ----------
12V 0.4V

Solving for RL2


RL2 + 10M = (10M x 12V)/0.4V

RL2 = [(10M x 12V)/0.4V] - 10M

RL2 = 290,000,000 ohms which
represents a parasitic (leakage)
load on the battery of
12/290M ~ 41 NANOAmps

For this leakage to take say, an 18AH battery
down to 1/2 capacity would require . . .

9,000,000,000 nAHr/41nA = 220 Million hours
or roughly 25,000 years.

The value for leakage current is generally
always cited on data sheets for diodes but it's
so tiny that only in very specialized, small
signal applications is it significant to the
design. We CAN measure it, as you have done,
but in the airframe, its more of a curiosity
than a concern.

Also, reverse leakage varies widely with temperature,
applied voltage and batch-to-batch variations.

Going back to the drawing I show another 'leakage'
resistor (RL1) that is internal to the battery.
All batteries have one of these and depending
on chemistry and temperature, it too will discharge
the battery. Most secondary SLVA and Lithium products are
good on the shelf for 1-2 years.

I suggest that leakage inside the battery is
of far greater concern than diode leakage(s)
outside the battery.



Bob . . .

Un impeachable logic: George Carlin asked, "If black boxes
survive crashes, why don't they make the whole airplane
out of that stuff?"


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